1 条题解
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#include<bits/stdc++.h> using namespace std; using ll=long long; const int N = 2e6+10; const ll mod = 1e9+7; constexpr ll ksm(ll a,ll b){ ll r = 1; while(b){ if(b&1)r=r*a%mod; a=a*a%mod; b>>=1; } return r; } constexpr ll inv2 = ksm(2, mod-2); constexpr ll sum(ll n){n%=mod;return n*(n+1)%mod*inv2%mod;} ll n; ll p[N],tot; bool vis[N]; ll id1[N],id2[N],v[N],m; ll get(ll x){return x<N?id1[x]:id2[n/x];} ll g1[N],g2[N],g[N]; ll f(ll P,ll K){return (P^K)%mod;} ll S[N]; int main(){ for(int i=2;i<N;i++){ if(!vis[i])p[++tot]=i; for(int j=1;j<=tot && i*p[j]<N;j++){ vis[i*p[j]]=1; if(i%p[j]==0)break; } } cin>>n; for(ll l=1,r;l<=n;l=r+1){ r=n/(n/l); v[++m]=n/l; if(v[m]<N)id1[v[m]]=m; else id2[n/v[m]]=m; g1[m]=(sum(v[m])+mod-1)%mod, g2[m]=(v[m]-1+mod)%mod; } for(int j=1;j<=tot;j++){ for(int i=1;i<=m && p[j]<=v[i]/p[j];i++){ g1[i] = (g1[i] - p[j]*(g1[get(v[i]/p[j])]-g1[get(p[j-1])]+mod)%mod + mod) % mod; g2[i] = (g2[i] - (g2[get(v[i]/p[j])] - g2[get(p[j-1])])%mod + mod) % mod; } } for(int i=1;i<=m;i++)g[i]=(g1[i]-g2[i]+mod + (v[i]>=2?2:0))%mod; for(int i=1;i<=m;i++)S[i]=g[i]; for(int j=tot-1;j>=0;j--){ for(int i=1;i<=m && p[j+1]<=v[i]/p[j+1];i++){ for(ll w=p[j+1],k=1;w<=v[i]/p[j+1];w*=p[j+1],++k){ S[i] = (S[i] + f(p[j+1],k)*(S[get(v[i]/w)]-g[get(p[j+1])]+mod)%mod + f(p[j+1],k+1))%mod; } } } for(int i=1;i<=m;i++)S[i]=(S[i]+1)%mod; sort(S+1,S+1+m); m=unique(S+1,S+1+m)-S-1; ll ans = 0; for(int i=1;i<=m;i++)ans^=S[i]; cout << ans << '\n'; return 0; }
- 1
信息
- ID
- 9715
- 时间
- 10000ms
- 内存
- 512MiB
- 难度
- 10
- 标签
- 递交数
- 2
- 已通过
- 1
- 上传者