1 条题解
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0

#include <bits/stdc++.h> #define lg2(x) (31 - __builtin_clz(x)) typedef long long ll; const int N = 135400, mod = 998244353, root = 31; typedef int vec[N], *pvec; int n, q; vec l, f, g, r; inline void add(int &x, const int y) {x += y - mod, x += x >> 31 & mod;} ll PowerMod(ll a, int n, ll c = 1) {for (; n; n >>= 1, a = a * a % mod) if (n & 1) c = c * a % mod; return c;} namespace Poly { int l, n; vec rev, x, y; void NTT_init(int len) { if (l == len) return; n = 1 << (l = len); ll g = PowerMod(root, 1 << (23 - l)); *x = 1, *rev = 0; for (int i = 1; i < n; ++i) x[i] = x[i - 1] * g % mod, rev[i] = rev[i >> 1] >> 1 | (i & 1) << (l - 1); } void DNTT(int *d, int *t) { int i, *j, *k, len = 1, delta = n, R; for (i = 0; i < n; ++i) t[rev[i]] = d[i]; for (i = 0; i < l; ++i) { delta >>= 1; for (k = x, j = y; j < y + len; k += delta, ++j) *j = *k; for (j = t; j < t + n; j += len << 1) for (k = j; k < j + len; ++k) { R = (ll)y[k - j] * k[len] % mod; k[len] = (*k - R < 0 ? *k - R + mod : *k - R); *k = (*k + R >= mod ? *k + R - mod : *k + R); } len <<= 1; } } vec B1, B2, B3; void Mul(int degA, int degB, pvec a, pvec b, pvec c) { if (!degA && degB == 1) {*c = (ll)*a * *b % mod, c[1] = *a * b[1] % mod; return;} if (degA == 1 && !degB) {*c = (ll)*a * *b % mod, c[1] = a[1] * *b % mod; return;} NTT_init(lg2(degA + degB) + 1); int i; ll iv = mod - (mod - 1) / n; memcpy(B1, a, (degA + 1) << 2), memset(B1 + (degA + 1), 0, (n - degA - 1) << 2); memcpy(B2, b, (degB + 1) << 2), memset(B2 + (degB + 1), 0, (n - degB - 1) << 2); DNTT(B1, B3), DNTT(B2, B1); for (i = 0; i < n; ++i) B1[i] = (ll)B1[i] * B3[i] % mod; DNTT(B1, B3), std::reverse(B3 + 1, B3 + n); for (i = 0; i <= degA + degB; ++i) c[i] = B3[i] * iv % mod; } } void solve(int L, int R) { int i, M = (L + R + 1) / 2; if (L + 1 == R) { add(f[L], f[L - 1]), add(f[L], g[L - 1]), g[L] = f[L] * (L - 1ll) % mod; return; } solve(L, M); if (L) { Poly::Mul(M - L - 1, R - L - 1, f + L, g, r); for (i = M; i < R; ++i) add(f[i], r[i - L]); Poly::Mul(R - L - 1, M - L - 1, f, g + L, r); for (i = M; i < R; ++i) add(f[i], r[i - L]); } else { Poly::Mul(M - 1, M - 1, f, g, r); for (i = M; i < R; ++i) add(f[i], r[i]); } solve(M, R); } int main() { int i, j, p, ans; scanf("%d%d", &q, &n), f[2] = 2, solve(0, n), *f = 1, f[1] = 2; for (; q; --q) { for (i = 1; i <= n; ++i) scanf("%d", l + i); for (ans = 1, i = (l[n] == n ? 1 : n + 2); i <= n; ++i) { for (p = 0, j = i - 1; j > i - l[i]; j -= l[j], ++p); if (j != i - l[i]) break; ans = (ll)ans * f[p] % mod; } printf("%d\n", i == n + 1 ? ans : 0); } return 0; }
- 1
信息
- ID
- 4683
- 时间
- 1000ms
- 内存
- 256MiB
- 难度
- 10
- 标签
- 递交数
- 3
- 已通过
- 1
- 上传者