1 条题解
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0
#include <cmath> #include <cstdio> #include <cstring> #include <iostream> #include <algorithm> using namespace std; inline int read() { int res = 0; bool bo = 0; char c; while (((c = getchar()) < '0' || c > '9') && c != '-'); if (c == '-') bo = 1; else res = c - 48; while ((c = getchar()) >= '0' && c <= '9') res = (res << 3) + (res << 1) + (c - 48); return bo ? ~res + 1 : res; } const int N = 1e5 + 5; int n, tn, f[N]; struct cyx { int l, r, v; } a[N], b[N]; bool comp1(cyx a, cyx b) { if (a.l != b.l) return a.l < b.l; return a.r < b.r; } bool comp2(cyx a, cyx b) { if (a.r != b.r) return a.r < b.r; return a.l < b.l; } int findx(int l, int r, int val) { while (l <= r) { int mid = l + r >> 1; if (a[mid].r < val) l = mid + 1; else r = mid - 1; } return r; } int main() { int i, x, y, tmpn; tmpn = read(); for (i = 1; i <= tmpn; i++) a[i].l = read() + 1, a[i].r = tmpn - read(); sort(a + 1, a + tmpn + 1, comp1); for (i = 1; i <= tmpn; i++) if (a[i].l <= a[i].r) b[++tn] = a[i]; for (i = 1; i <= tn; i++) if (i == 1 || b[i].l != b[i - 1].l || b[i].r != b[i - 1].r) a[++n] = b[i], a[n].v = 1; else if (a[n].v < a[n].r - a[n].l + 1) a[n].v++; sort(a + 1, a + n + 1, comp2); f[1] = a[1].v; for (i = 2; i <= n; i++) { int nxt = findx(1, i - 1, a[i].l); f[i] = max(f[i - 1], f[nxt] + a[i].v); } cout << tmpn - f[n] << endl; return 0; }
- 1
信息
- ID
- 3963
- 时间
- 1000ms
- 内存
- 128MiB
- 难度
- 8
- 标签
- 递交数
- 21
- 已通过
- 5
- 上传者